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select username,count(*) as count from hk_test group by username having count>1;
SELECT username,count(username) as count FROM hk_test GROUP BY username HAVING count(username) >1 ORDER BY count DESC;
这种方法只是统计了该字段重复对应的具体的个数场景二:列出username字段重复记录的具体指:1
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select * from hk_test where username in (select username from hk_test group by username having count(username) > 1)
SELECT username,passwd FROM hk_test WHERE username in ( SELECT username FROM hk_test GROUP BY username HAVING count(username)>1) 但是这条语句在mysql中效率太差,感觉mysql并没有为子查询生成临时表。在数据量大的时候,耗时很长时间
解决方法:场景三:查看两个字段都重复的记录:比如username和passwd两个字段都有重复的记录:1
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select * from hk_test a
where (a.username,a.passwd) in (select username,passwd from hk_test group by username,passwd having count(*) > 1)
场景四:查询表中多个字段同时重复的记录:1
select username,passwd,count(*) from hk_test group by username,passwd having count(*) > 1
参数说明:user_name为要查找的重复字段.count用来判断大于一的才是重复的.user_table为要查找的表名.group by用来分组having用来过滤.mysql密码修改,wind mysql 5.6安装,mysql timeout的单位,MySQL8的下载,mysql视图汉化,php 删除mysql数据php单选题附答案,域名交易系统php,给php程序员建议 知乎,php 中文字符,php项目怎么绑定域名访问,thinkphp 日期类,php 取数组前五个,php op array,php 数组换行